Find the slope of a line tangent to the given curve at the point P by finding the limit of the slopes of the secant lines PQ as Q approaches P.y = 5x2 - 5; P is (3, 40); let Q have x-values of 2.5, 2.9, 2.99, 2.999
A. Slopes: 7.5, 9.5, 9.95, 9.995
m = 10
B. Slopes: 27.5, 29.5, 29.95, 29.995
m = 30
C. Slopes: 22.5, 24.5, 24.95, 24.995
m = 25
D. Slopes: 12.5, 14.5, 14.95, 14.995
m = 15
Answer: B
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