Solve the problem.Eye color (brown or blue) of a child is determined by which of two alleles (B for the dominant brown allele or b for the recessive blue allele) the child receives from each of its parents. A person is considered heterozygous for a trait if their two alleles are different than each other. If two heterozygous parents (Bb) have children, we expect 1 out of every 4 of those children to have blue eyes. How many blue-eyed children would we expect out of 860 children born to two heterozygous parents?
A. 172 blue-eyed children
B. 645 blue-eyed children
C. 430 blue-eyed children
D. 215 blue-eyed children
Answer: D
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Find the torsion of the space curve.r(t) = (6t sin t + 6 cos t)i + (6t cos t) - 6 sin t)j - 6k
A. ? = 0 B. ? = 1 C. Undefined D. ? = -1
Simplify the expression. Include absolute value bars where necessary.
A. -8x + 2
B. 
C. -2x - 4
D. -2x + 4
Graph the function. Specify the intervals over which the function is increasing and the intervals where it is decreasing.y = - 
A. Decreasing -? < x < 0 and 0 < x < ?
B. Increasing -? < x < 0 and 0 < x < ?
C. Decreasing -? < x < 0
Increasing 0 < x < ?
D. Increasing -? < x < 0
Decreasing 0 < x < ?
Solve the problem.A study of consumer smoking habits includes 180 people in the 18-22 age bracket (60 of whom smoke), 130 people in the 23-30 age bracket (33 of whom smoke), and 100 people in the 31-40 age bracket (29 of whom smoke). If one person is randomly selected from this sample, find the probability of getting someone who is age 18-22 or does not smoke.
A. 1.141 B. 0.667 C. 0.849 D. 0.293