A group of engineers has landed on the moon, and they wish to determine the mass of some rocks. They have a spring scale calibrated to read pounds mass at a location where the acceleration of gravity is 
One of the moon rocks gives a reading of 18.76 on this scale. What is its mass? What is its weight on the moon? Take g(moon) 
What will be an ideal response?
The force on the scale, whether on earth or on the moon, can be written at 
and it is the force that is
actually measured by the scale. The reading (displayed in 
) is therefore proportional to the actual mass and proportional to the gravitational constant., It can be written as 
where A, the calibration constant for
the scale, is numerically equal to 
On earth, where 
A = 1. On the moon, where 
A
needs to be corrected by the ratio of g on the moon to g on earth. A = 5.32/32.186 = 0.1653. So, on the moon, 
The true mass of the rock is 
Its weight on the moon is numerically equal to the reading. It is 
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