A boy is two years younger than his sister. Three years ago, the sum of their ages was 48. What is the boy’s age?

Question

A. 12
B. 24
C. 26
D. 32
E. 40

Answer 1

Ans: Let boy's age be B

Then sister's age is B + 2 Since their ages summed to 48, 3 years ago, their ages sum to 48 + 6, or 54, now We then get: B + B + 2 = 54 2B = 52 Boy's age, or

B=52/2=26