Solve the problem.A projectile is fired from a height of 8.9 feet with an initial velocity of 117 ft/sec at an angle of 47° with the horizontal. The parametric equations for the path of the projectile are x = (117 cos 47°)t, and y = 8.9 + (117 sin 47°)t - 16t2,where x and y are in feet and t is in seconds. Determine the rectangular equation describing the path of the projectile.
A. y = 8.9 + 117x tan 47° - 
x2
B. y = 8.9 + x tan 47° - 
x2
C. y = 8.9 + 117x tan 47° - 
x2
D. y = 8.9 + x tan 47° - 
x2
Answer: B
Mathematics
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