Solve the initial value problem.Differential Equation:   = (t4 + 5t2)i + 4tjInitial Condition:  r(0) = 5i + 7j

A. r(t) =  i + (2t2 + 5)j
B. r(t) =  i + (t2 + 7)j
C. r(t) =  i + (2t2 + 7)j
D. r(t) =  i + 2t2j

Answer: C

Mathematics

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