If f is the frequency of the emitted radiation, and h is Planck's constant (equal to 6.63 × 10^–34 J ? s), the energy E each emitted quantum of energy has in Planck's explanation of blackbody radiation is:
a. E = h / f.
b. E = h f.
c. E = h + f.
d. E = mc2.
e. E = f / h.
b
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