Determine the ground water infiltration rate for a new four-lane pavement with the following characteristics:
Lane width = 12 ft
Shoulder width = 6 ft
Length of contributing transverse cracks (Wc) = 40 ft
Rate of infiltration (Kp) = 0.05 ft3/day/ft2
Spacing of transverse cracks = 40 ft
What will be an ideal response?
Determine the width of granular base.
W = (number of lanes) × (lane width) + (shoulder width) × 2
W = (4 × 12) + (6 × 2)
W = 60 ft
Since this is a new pavement,
Nc = N + 1
Nc = 5
Use Equation 16.24 to determine infiltration rate (assume Ic = 2.4):
qi = (2.4) [(5 / 60) + (40 / (60)(40))] + 0.05
qi = 0.29 ft3 / day / ft2
Therefore, the ground water infiltration rate will be 0.29 ft3/day/ft2 for this new
pavement section.
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