An electron moves horizontally across the Earth’s equator at a speed of 2.50 × 106 m/s and in a direction 35.08 N of E. At this point, the Earth’s magnetic field has a direction due north, is parallel to the surface, and has a value of 3.00 × 1025 T. What is the force acting on the electron due to its interaction with the Earth’s magnetic field?

1.6.88 × 10-18 N due west
2.6.88 × 10-18 N toward the Earth’s surface
3.9.83 × 10-18 N toward the Earth’s surface
4.9.83 × 10-18 N away from the Earth’s surface
5.4.00 × 10-18 N away from the Earth’s surface


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Physics & Space Science

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