Solve the problem.Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, find the body's position at time t.a = 20, v(0) = 13, s(0) = -14
A. s = 10t2 + 13t
B. s = 20t2 + 13t - 14
C. s = 10t2 + 13t - 14
D. s = -10t2 - 13t - 14
Answer: C
Mathematics
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A. 6x2y2(x5y7 - 6x3y4 - 3) B. 6(x7y9 - 6x5y6 - 3x2y2) C. 6x2(x5y9 - 6x3y6 - 3y2) D. -6x2y2(-x5y7 - 6x3y4 + 3)
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