Matter Waves: After an electron has been accelerated through a potential difference of 0.15 kV, what is its de Broglie wavelength? (e = 1.60 × 10-19 C, melectron = 9.11 × 10-31 kg, h = 6.626 × 10-34 J ? s)
A. 0.10 nm
B. 1.0 nm
C. 1.0 mm
D. 1.0 cm
Answer: A
Physics & Space Science
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