Write as a decimal.78%
A. 7.8
B. 0.78
C. 0.67
D. 0.078
Answer: B
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Find the work done by F over the curve in the direction of increasing t.F = xyi + 8j + 2xk; C: r(t) = cos 4ti + sin 4tj + tk, 0 ? t ? 
A. W = 
B. W = 
C. W = 0
D. W = 
Estimate the error in the quadratic approximation of the given function at the origin over the given region.
A. |E(x, y)| ? 0.864 B. |E(x, y)| ? 0.432 C. |E(x, y)| ? 0.216 D. |E(x, y)| ? 0.288
Provide an appropriate response. A route from Albany, New York to Bangor, Maine takes a salesman four days. He keeps an accurate record of each leg of his journey. His record shows: 34, 57, 48, 64, 35, 28, 21, 52, 26, and 52. How far is it from Albany to Bangor for the salesman?
A. 417 miles B. 41.7 miles C. 420 miles D. 365 miles
Solve the problem.A company that produces handbags has found that revenue from the sales of the handbags is $10 per handbag, less sales costs of $100. Production costs are $125, plus $9 per handbag. Profit (P) is given by revenue (R) less cost (C), so the company must find the production level x that makes P > 0, that is, R - C > 0.(a) Write an expression for revenue, R, letting x represent the production level (number of handbags to be produced.)(b) Write an expression for production costs C in terms of x.(c) Write an expression for profit P, and then solve the inequality P > 0.(d) Describe the solution in terms of the problem.
A. (a) R = 10x - 100; (b) C = 75 + 11x; (c) P = (10x - 100) - (75 + 11x) = x - 125; x > 125; (d) To make a profit, more than 125 handbags must be produced and sold. B. (a) R = 10x + 100; (b) C = 125 + 9x; (c) P = (10x + 100) - (125 + 9x) = x - 25; x > 25; (d) To make a profit, more than 25 handbags must be produced and sold. C. (a) R = 10x - 100; (b) C = 125 - 9x; (c) P = (10x - 100) - (125 - 9x) = x - 175; x > 175; (d) To make a profit, more than 175 handbags must be produced and sold. D. (a) R = 10x - 100; (b) C = 125 + 9x; (c) P = (10x - 100) - (125 + 9x) = x - 225; x > 225; (d) To make a profit, more than 225 handbags must be produced and sold.