Determine the number of possible positive and negative real zeros using Descartes’ Rule of Signs.
 figure 1.png)
(a) Positive real: exactly one; Negative real: exactly one
(b) Positive real: 2 or 0; Negative real: exactly 2
(c) Positive real: 4 or 0; Negative real: exactly one
(d) Positive real: exactly 4; Negative real: exactly one
(e) Positive real: 4, 2, or 0; Negative real: exactly one
(e) Positive real: 4, 2, or 0; Negative real: exactly one
You might also like to view...
Solve the problem.At a movie theater, 46 more people attended the early show than the late show. There were 324 people who saw the movie that night. How many people attended the late show?
A. 139 B. 278 C. 370 D. 185
Describe the solution set as an inequality and in interval notation. |x| ? 3
A. x ? -3 or x ? 3; (-?, -3] ? [3, ? ) B. 0 ? x ? 3; [0, 3] C. -3 ? x ? 3; [-3 , 3] D. the set of real numbers; (-?, ?)
Simplify.197.8 - 4.74 × 6.09
A. 194.91334 B. 1175.7354 C. 172.0434 D. 168.9334
Solve.The difference of a number and 7 is equal to the quotient of 12 and 4. Find the number.
A. -4 B. 4 C. 55 D. 10