Use a regular expression to count the number of digits, non-digit characters, whitespace characters and words in a string.

Question

What will be an ideal response?

Answer 1

```
# Count number of digits, characters, white space characters
# and words in a string.

import re

testString = raw_input( "Please input a string: " )

# split the string by digits, creating digits + 1 pieces
digits = len( re.split( "\d", testString ) ) - 1

if digits > 1:
print "There are %d digits in this string." % digits
elif digits == 1:
print "There is one digit in this string."
else:
print "There is no digit in this string."

characters = len( re.split( "\w", testString ) ) - 1

if characters > 1:
print "There are %d characters in this string." % \
characters
elif characters == 1:
print "There is one character in this string."
else:
print "These is no character in this string."

whitespaces = len( re.split( "\s", testString ) ) - 1

if whitespaces > 1:
print "There are %d white spaces in this string." \
% whitespaces
elif whitespaces == 1:
print "There is one white space in this string."
else:
print "There is no whitespace in this string."

words = len ( re.split( "\w+", testString ) ) - 1

if words > 1:
print "There are %d words in this string." % words
elif words == 1:
print "There is one word in this string."
else:
print "There is no word in this string."
```
Please input a string: Eight quick foxes jumped over 8 fences and 8 lazy
dogs.
There are 2 digits in this string.
There are 53 characters in this string.
There are 10 white spaces in this string.
There are 11 words in this string.