Potential: After a proton with an initial speed of 1.50 × 105 m/s has increased its speed by accelerating through a potential difference of 0.100 kV, what is its final speed? (e = 1.60 × 10-19 C , mproton = 1.67 × 10-27 kg)

A. 4.56 × 105 m/s
B. 2.04 × 105 m/s
C. 3.55 × 105 m/s
D. 8.80 × 105 m/s
E. 1.55 × 106 m/s


Answer: B

Physics & Space Science

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