A myopic (nearsighted) dancer wears eyeglasses that allow him to have clear distant vision. The power of the lenses of his eyeglasses is -3.00 diopters. Without eyeglasses, what is the far point of the dancer?

A) 0.50 m B) 0.17 m C) 0.42 m D) 0.33 m E) 0.25 m

D

Physics & Space Science

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Thin Lenses: Two thin lenses, one a converging lens and the other a diverging lens, are separated by 1.00 m along the same principal axis, as shown in the figure. The magnitude of the focal length of the converging lens is 25 cm, while the magnitude of the focal length of the diverging lens is 40 cm. An object 8.25 cm tall is placed 35 cm to the left of the converging lens.(a) Where is the final image produced by this combination of lenses? (Give your answer relative to the diverging lens.)(b) Compared to the object, is the final image upright or inverted? Is it real or virtual?

What will be an ideal response?

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How did Planck modify the classical theory of blackbody radiation to correctly determine his radiation law?

A.He found that the blackbody model was incorrect for purposes of theory B.He accepted the Stefan-Boltzmann law C. He assumed light was absorbed and emitted in quanta D.He realized that the charge of the electron was not quantized E.He proved the necessity of relativistic considerations

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The Sun's path, as viewed from the equator, is highest in the sky on ________

A) the winter solstice B) the day when Earth is closest to the Sun C) the summer solstice D) the spring and fall equinoxes

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The work done by static friction can be:

a. positive. b. negative. c. zero. d. Any of the above.

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