Assume that Y is normally distributed N? (??, ?2?). Moving from the mean ?(??) 1.96 standard deviations to the left and 1.96 standard deviations to the? right, then the area under the normal p.d.f.? is:
A) 0.67
B) 0.05
C) 0.95
D) 0.33
Ans: C) 0.95
Z = 1.96 = .025
.025 + .025 = .05
1 - .05 = .95
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