Find the slope of a line tangent to the given curve at the point P by finding the limit of the slopes of the secant lines PQ as Q approaches P.y = 7x - 7x2; P is (5, -140); let Q have x-values of 4.5, 4.9, 4.99, 4.999
A. Slopes: -31.5, -34.3, -34.93, -34.993
m = -35
B. Slopes: -31.5, -34.3, -34.93, -34.993
m = -28
C. Slopes: -59.5, -62.3, -62.93, -62.993
m = -63
D. Slopes: -66.5, -69.3, -69.93, -69.993
m = -70
Answer: C
Mathematics
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