(Printing the Decimmal Equivalent of a Binary Number) Input an integer containing only 0s and 1s (i.e., a “binary” integer) and print its decimal equivalent. Use the modulus and division operators to pick off the “binary” number’s digits one at a time from right to left. Much as in the decimal number system, where the rightmost digit has a positional value of 1, the next digit left has a positional value of 10, then 100, then 1000, and so on, in the binary number system the rightmost digit has a positional value of 1, the next digit left has a positional value of 2, then 4, then 8, and so on. Thus the decimal number 234 can be interpreted as 2 * 100 + 3 * 10 + 4 * 1. The decimal equiv- alent of binary 1101 is 1 * 1 + 0 * 2 + 1 * 4 + 1 * 8 or 1 + 0 + 4 + 8, or 13. [Note: To learn more abo

Question

What will be an ideal response?

Answer 1

```
// Convert a binary value to its decimal equivalent.
#include
using namespace std;

int main()
{
int binary; // binary value
int bit = 1; // bit positional value
int decimal = 0; // decimal value

// prompt for and read in a binary number
cout << "Enter a binary number: ";
cin >> binary;

// convert to decimal equivalent
while ( binary != 0 )
{
decimal += binary % 10 * bit;
binary /= 10;
bit *= 2;
} // end while loop

cout << "Decimal is: " << decimal << endl;
} // end main
```