Solve the problem.If an object is moving at a constant speed s (in miles per hour), then s = dt-1, where d is the distance traveled (in miles) and t is the time (in hours).a. Simplify the right-hand side of the equation.b. Substitute 153 for d and 3 for t in the equation you found in part (a), and solve for s. What does your result mean in this situation?
A. a. s = 
b. 51; an object that travels 3 miles in 153 hours at a constant speed is traveling at a speed of 51 miles per hour.
B. a. s = dt
b. 459; an object that travels 153 miles in 3 hours at a constant speed is traveling at a speed of 459 miles per hour.
C. a. s = dt
b. 459; an object that travels 3 miles in 153 hours at a constant speed is traveling at a speed of 459 miles per hour.
D. a. s = 
b. 51; an object that travels 153 miles in 3 hours at a constant speed is traveling at a speed of 51 miles per hour.
Answer: D
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