Find the particular solution for the initial value problem. x  = 4x2e2x; y(0) = 15

A. y = 4xe2x - 2e2x + 17
B. y = 2xe2x - e2x + 16
C. y = 4xe2x - e2x + 16
D. y = 2xe2x + 15


Answer: B

Mathematics

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