When a shallow copy of an Array class is made, the pointers of the original and copy point to the same dynamic array because:
A. the address of the pointer of one Array is copied into the pointer of the other Array
B. there can only be one dynamic array at any one time
C. every object made from an Array class has to point to the same place in the heap
D. if they didn’t, one would be a dangling pointer
A
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