A crest vertical curve connects a +4.44% grade and a –6.87% grade. The PVI is at station 43+50.00 at an elevation of 1240.00 ft. The design speed is 30 mi/h. Determine the following below:
(a) The length of the vertical curve using the AASHTO method (“K” factors)
(b) The station of the BVC
(c) The elevation of the BVC
(d) The station of the EVC
(e) The elevation of the EVC
(f) The station of the high point
(g) The elevation of the high point
(h) The elevation of station 44+23.23
What will be an ideal response?
From Table 15.4, K = 19
(a) L = KA = (19)|–4.44-6.87| = (19)(11.31) = 214.89 ft
(b) Station of BVC = (43+50) – (214.89 ft)/2 = 42+42.55
(c) Elevation of BVC = 1240.00 – (0.0444)(214.89 ft/2) = 1235.23 ft
(d) Station of EVC = (43+50) + (214.89 ft)/2 = 44+57.45
(e) Elevation of EVC = 1240.00 – (0.0687)(214.89 ft/2) = 1232.62 ft
(f) Station of the high point = (42+42.55) + (214.90)(4.44)/(11.31) = 43+26.91
(g) Elevation of the high point = 
(h) Elevation of station 44+23.23 = 
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