Factor using substitution.6z6 - 5z3 - 6

A. (2z3 + 3)(3z3 - 2)
B. (6z3 + 1)(z3 - 6)
C. (2z3 - 3)(3z3 + 2)
D. (6z3 - 3)(z3 + 2)

Answer: C

Mathematics

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