Solve.The length and width of a rectangle must have a sum of 66 feet. Find the dimensions of the rectangle whose area is as large as possible.

A. length  ft; width  ft
B. length 33 ft; width 99 ft
C. length 33 ft; width 33 ft
D. length 32 ft; width 34 ft


Answer: C

Mathematics

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a.
b.
c.
d.
e.

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A. 2i
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D.

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Multiply. Simplify by combining like terms.(x2 - 6xy2)(x2y - 12y)

A. x4y - 6x3y3 - 12x2y + 72xy3 B. x4y - 18x3y3 + 72xy3 C. x4y + 6x3y3+ 12x2y + 72xy3 D. x4y - 18x2y + 72xy3

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