Solve.The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a screen 5 ft from a light is 2 foot-candles, find the intensity on a screen 10 ft from the light.
A. 2 foot-candles
B. 
foot-candle
C. 1
foot-candles
D. 
foot-candle
Answer: B
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State the domain and range in interval notation.f(x) = -7(x - 4)2 - 9
A. domain: [-9, ?); range: (-?, ?) B. domain: (-?, -9]; range: (-?, ?) C. domain: (-?, ?); range: [-9, ?) D. domain: (-?, ?); range: (-?, -9]
Find the missing parts of the triangle. A = 65.3°a = 2.15 kmb = 2.25 kmIf necessary, round angles to the nearest tenth and side lengths to the nearest hundredth.
A. B1 = 42.8°, C1 = 71.9°, c1 = 1.61 km B2 = 6.6°, C2 = 108.1°, c2 = 0.27 km B. B1 = 71.9°, C1 = 42.8°, c1 = 1.61 km B2 = 108.1°, C2 = 6.6°, c2 = 0.27 km C. no such triangle D. B = 71.9°, C = 42.8°, c = 1.61 km
If you have the following function, f ( x ) = -9| x | + 5, compute f (4), f (-2), f (9), f (-7)
A. f (4) = –31, f (-2) = -13, f (9) = –76, f (-7) = -58 B. f (4) = –30, f (-2) = -14, f (9) = –75, f (-7) = -59 C. f (4) = –30, f (-2) = -11, f (9) = –77, f (-7) = -56 D. f (4) = –28, f (-2) = -15, f (9) = –73, f (-7) = -60 E. f (4) = 31, f (-2) = 13, f (9) = 76, f (-7) = 58
Find the indicated function.Functions f and g are defined by the table. Find f + g. 
A. 
B. 
C. 
D. 