A wood member weighs 10 lb. It is now fully dried, i.e., until it contains no water. Its dry weight is 8 lb. What was the moisture content (MC) in its original, moist condition?
What will be an ideal response?
The amount of water in wood in its original condition = (10 - 8) = 2 lb
MC = [(weight of water in wood)/(weight of dry wood)] × 100 = [2/8] × 100 = 25%
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