The half-life of 14C is 5,730 years. If you test a fossilized bone and find that it has 1/8th the 14C as a modern bone, you could conclude that it is approximately years old.
A. 5,730 × 3 = 17,190
B. 5,730 × 2 = 11,460
C. 5,730 × 1 = 5,730
D. 5,730 / 8 = 716
E. 5,730 × 8 = 42,960
A. 5,730 × 3 = 17,190
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