In the circuit shown below, let
Use mesh analysis to find mesh currents I1, I2, and I3. Also, find V1 and V2.
Vs=9;
R1=1000;R2=400;R3=500;R4=1200;gm=0.0004
syms I1 I2 I3
[I1,I2,I3]=solve(-Vs+R2*(I2-I1)+R3*(I2-I3),...
R1*I1+R4*I3+R3*(I3-I2)+R2*(I1-I2),...
I3-I1==gm*R3*(I2-I3),I1,I2,I3)
V1=R3*(I2-I3)
V2=R4*I3
IR4=I3
IR1=I1
IR2=I2-I1
IR3=I2-I3
SumI=-IR2+IR3+gm*V1
I1=vpa(I1,7)
I2=vpa(I2,7)
I3=vpa(I3,7)
V1=vpa(V1,7)
V2=vpa(V2,7)
IR4=vpa(IR4,7)
IR1=vpa(IR1,7)
IR2=vpa(IR2,7)
IR3=vpa(IR3,7)
SumI=vpa(SumI,7)
Answers:
I1 =
0.003089054
I2 =
0.01410946
I3 =
0.004925788
V1 =
4.591837
V2 =
5.910946
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