Solve the problem.A projectile is fired from a height of 7.5 feet with an initial velocity of 195 ft/sec at an angle of 52° with the horizontal. The parametric equations for the path of the projectile are x = (195 cos 52°)t, and y = 7.5 + (195 sin 52°)t - 16t2,where x and y are in feet and t is in seconds. Determine the maximum height reached by the projectile. Round your answer to the nearest tenth of a foot.
A. 383.9 ft
B. 376.4 ft
C. 745.4 ft
D. 368.9 ft
Answer: B
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