Use the Principle of Mathematical Induction to show that the statement is true for all natural numbers n.1 + 4 + 7 + ... + (3n - 2) =
(3n - 1)
What will be an ideal response?
First we show that the statement is true when n = 1.
For n = 1, we get 1 = (3(1) - 1) = 1.
This is a true statement and Condition I is satisfied.
Next, we assume the statement holds for some k. That is,
is true for some positive integer k.
We need to show that the statement holds for k + 1. That is, we need to show that
So we assume that is true and add the next term,
, to both sides of the equation.
1 + 4 + 7 + ... + (3k - 2) + 3(k + 1) - 2 = (3k - 1) + 3(k + 1) - 2
= [k(3k - 1) + 6(k + 1) - 4]
= (3k2 - k + 6k + 6 - 4)
= (3k2 + 5k + 2)
= (k + 1)(3k + 2)
= (3k + 3 - 1)
= (3(k + 1) - 1)
Condition II is satisfied. As a result, the statement is true for all natural numbers n.
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