Calculate the load center length for a branch circuit consisting of the following noncontinuous loads
125A at 80' from the source
75A at 110' from the source
50A at 100' from the source
a. 95.1'
b. 92'
c. 93'
d. 94.6'
c. 93'
125A x 80' = 10,000
75A x 110' = 8,250
50A x 100' = 5,000
Find the sum of the results, and divide it by the sum of the individual loads:
10,000 + 8,250 + 5,000 = 23,250
125A + 75A + 50A = 250A
23,250 รท 250A = 93'
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