Solve the problem.Suppose that a hair dryer operates on a voltage that can be represented by the relation
and that it draws a current represented by the relation
where t is time measured in seconds. The power consumed by the appliance is P = VI. Graph the power in
by
and use an identity to write the expression for the power in the
form where a, k, and d are constants.
A. P = 400 cos(120?t) + 400
[0, 0.04, 0.01] by [-200, 2000, 200]
B. P = 800 cos(240?t) + 800
[0, 0.04, 0.01] by [-200, 2000, 200]
C. P = -400 cos(240?t) + 400
[0, 0.04, 0.01] by [-200, 2000, 200]
D. P = 400 cos(240?t) + 400
[0, 0.04, 0.01] by [-200, 2000, 200]
Answer: D
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A.
B.
C.
D.
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A.
B.
C.
D.