Solve the problem.Suppose that a hair dryer operates on a voltage that can be represented by the relation  and that it draws a current represented by the relation  where t is time measured in seconds. The power consumed by the appliance is P = VI. Graph the power in  by  and use an identity to write the expression for the power in the

form  where a, k, and d are constants.



A. P = 400 cos(120?t) + 400
[0, 0.04, 0.01] by [-200, 2000, 200]

B. P = 800 cos(240?t) + 800
[0, 0.04, 0.01] by [-200, 2000, 200]

C. P = -400 cos(240?t) + 400
[0, 0.04, 0.01] by [-200, 2000, 200]

D. P = 400 cos(240?t) + 400
[0, 0.04, 0.01] by [-200, 2000, 200]


Answer: D

Mathematics

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