What is the cardiac output, by using the direct Fick method, for a patient with the following he-modynamic values? PaO2 = 80 mm Hg SaO2 = 90% Hb = 14 gm% PO2 = 35 mm Hg SO2 = 65% PB = 760 mm Hg O2 = 210 mL/min
a. 3.5 mL/min c. 5.83 mL/min
b. 4.36 mL/min d. 6.15 mL/min
ANS: A
CaO2 = (Hb ? 1.34) SaO2 + (SaO2 ? 0.003).
CaO2 = (14 gm% ? 1.34) 0.90 + (80 mm Hg ??0.003).
CaO2 = 17.12 vol%.
CO2 = (Hb ? 1.34) SO2 + (PO2 ? 0.003).
CO2 = (14 gm% ? 1.34) 0.65 + (35 ? 0.003).
CO2 = 12.3 vol%.
Q = O2 ÷ (CaO2 – CO2) 10.
Q = 210 mL/min ÷ (17.12 mL/100 mL – 12.3 mL/100mL) 10.
Q = 4.36 mL/min.
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