Solve the initial value problem.
= 5t + sec2 t, r(-?) = 1
A. r = 5 + tan t - 4
B. r = 
t2 + cot t + 1 - 
?2
C. r = 5t2 + tan t + 1 - 5?2
D. r = 
t2 + tan t + 1 - 
?2
Answer: D
You might also like to view...
Calculate the Taylor polynomial of second order that approximates f(x, y) near a.f(x, y) = 
, a = (4, 4)
A. 4 + 
(x - 4) + 
(y - 4) - 
(x - 4)2 - 
(x - 4)(y - 4) - 
(y - 4)2
B. 4 + 
(x - 4) + 
(y - 4) - 
(x - 4)2 - 
(x - 4)(y - 4) - 
(y - 4)2
C. 4 + 
(x - 4) + 
(y - 4) + 
(x - 4)2 + 
(x - 4)(y - 4) + 
(y - 4)2
D. 4 + 
(x - 4) + 
(y - 4) - 
(x - 4)2 + 
(x - 4)(y - 4) - 
(y - 4)2
Graph the parabola and label the vertex. Find the x-intercept.x = 
y2 + 3
A. vertex (3, 0), x-intercept (3, 0)
B. vertex (- 3, 0), x-intercept (- 3, 0)
C. vertex (3, 0), x-intercept (3, 0)
D. vertex (- 3, 0), x-intercept (- 3, 0)
Find the perimeter. Use 3.14 for ? when needed.
A. 20.56 cm B. 6.28 cm C. 12.56 cm D. 16.56 cm
Simplify the root, if possible.
A. cannot be simplified
B. 
C. 7m + 4n
D. (7m + 4n)2