The channel from a space probe to earth has a bandwidth B = 106 Hz. The channel capacity when the probe is 103 km from earth is C =107 bps = 10 Mbps. Using the inverse square law to describe the signal power loss, the capacity when the probe is at 2 x 103 km from earth equals _____ Mbps. Assume that the noise power is constant.
Fill in the blank(s) with the appropriate word(s).
og2(1+?s2(?ro)/?N2) = C/B = 10 ??s2(?ro)/?N2 = 1023. At 2ro, ?s2(?ro)/?N2 = 1023/4 = 255.75 ? log2(255.75+1) = 8? C = 8B = 8 Mbps
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