Circular Motion of Charges: A proton having a speed of 3.0 × 106 m/s in a direction perpendicular to a uniform magnetic field moves in a circle of radius 0.20 m within the field. What is the magnitude of the magnetic field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg)

A. 0.080 T
B. 0.16 T
C. 0.24 T
D. 0.32 T
E. 0.36 T


Answer: B

Physics & Space Science

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