Write the formula for Newton's method and use the given initial approximation to compute the approximations x1 and x2. Round to six decimal places.f(x) = x2 - 6; x0 = 3

A. xn+1 = xn + x1 = 2.500000x2 = 2.450000
B. xn+1 = x1 = 3.000000x2 = 2.950000
C. xn+1 = xn - x1 = 3.500000x2 = 1.450000
D. xn+1 = x1 = 2.500000x2 = 2.450000


Answer: D

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