Given a simple circular curve with the following properties: D = 11°, bearing on incoming (back) tangent is N 89°27’25” E, bearing on outgoing (forward) tangent is S 60°10’05” E, the station of the PI = 22+69.77 Determine the following below:
(a) The intersection angle (?)
(b) The radius (R)
(c) The tangent (T)
(d) The external distance (E)
(e) The middle ordinate (M)
(f) The long chord (C)
(g) The length of the curve (L)
(h) Station of the PC
(i) Station of the PT
What will be an ideal response?
(a) ? = 180° – (89.45694° + 60.16806°) = 30.375°
(b) R = 5729.58 / 11 = 520.87 ft
(c) T = R tan (?/2) = (520.87) tan (30.375/2) = 141.39 ft
(d) 
(e) M = 520.87 [1 – cos (30.375/2)] = 18.19 ft
(f) C = 2(520.87) sin (30.375/2) = 272.91 ft
(g) L = (30.375)(520.87)?/180 = 276.14 ft
(h) Station PC = (22+69.77) – 141.39 ft = 21+28.38
(i) Station PT = (21+28.38) + 276.14 ft = 24+04.52
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