Part of a wreck from a ship weighs 500 N. It displaces 100 N of fluid. The buoyant force acting on it is

1) 100 N.
2) 250 N.
3) 500 N.

From this we can see that the buoyant force is equal to the
4) weight of the submerged object.
5) volume of fluid displaced.
6) difference between the weight of the object and the weight of fluid.
7) weight of fluid displaced.


Answer: 1, 7

Physics & Space Science

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