Give the output of the recursive function below when called with an argument of 5.

Question

```
void recursive( int i )
{
using namespace std;
if ( i < 8 )
{
i++;
recursive(i);
cout << i << " ";
}
}
```

a) 6 7 8
b) 5 6 7
c) 8 7 6
d) 7 6 5
e) None of the above. This is an infinite recursion if the function is called with argument 5.

Answer 1

c) 8 7 6

If this function is called with an argument of 5, the values of i that cause recursion are successively 5, 6, and 7, and each gets incremented to 6, 5, 8 which are stacked in that order.