Solve the following quadratic application using the given graph. An object is launched vertically in the air at 40 feet per second from a platform 50 feet above the ground. The height of the object above the ground (in feet) t seconds after launch is given by (i) How long does it take the object to reach its maximum height?(ii) What is the object's maximum height?(iii) Write the vertex as an ordered pair.(iv) Write the t-intercept as an ordered pair. What is the real-world meaning of the intercept?

Question

A. (i) 2.5 sec
(ii) The object's maximum height is 75 feet.
(iii) Vertex: (2.5, 50)
(iv) t-intercept: (3.41, 51); The object reaches a height of 51 feet after approximately 3.41 seconds.
B. (i) 1.25 sec
(ii) The object's maximum height is 50 feet.
(iii) Vertex: (1.25, 50)
(iv) t-intercept: (0, 51); The object hits the ground after approximately 51 seconds.
C. (i) 2.5 sec
(ii) The object's maximum height is 75 feet.
(iii) Vertex: (2.5, 75)
(iv) t-intercept: (3.12, 0); The object hits the ground after approximately 3.12 seconds.
D. (i) 1.25 sec
(ii) The object's maximum height is 75 feet.
(iii) Vertex: (1.25, 75)
(iv) t-intercept: (3.41, 0); The object hits the ground after approximately 3.41 seconds.

Answer 1

Answer: D