Air flows through a wet pipe at 298 K and 1 atm, and the diffusion coefficient of water vapor in air is 2.5x10²-5 m²/s. If the heat transfer coefficient is determined to be 80 W/m²ºC, the mass transfer coefficient is
(a) 0.0022 m/s
(b) 0.036 m/s
(c) 0.074 m/s
(d) 0.092 m/s
(e) 0.13 m/s
T=298 [K]
P=1 [atm]
h_heat=80 [W/m^2-C]
D_AB=2.5E-5 [m^2/s] "Table 14-2"
rho=1.184 [kg/m^3]
c_p=1007 [J/kg-C]
alpha=2.141E-5 [m^2/s]
h_heat=h_mass*rho*c_p*(alpha/D_AB)^(2/3)
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