What is the mean, standard deviation(s), and percent coefficient of variation (%CV) for the data shown in the following table? (Objective 1)
Table. Random urine creatinine sample that is assayed 10 consecutive times.
Sample number Random urine creatinine sample (mmol/L)
1 5.2
2 5.0
3 4.8
4 5.1
5 4.9
6 5.2
7 5.0
8 5.3
9 4.9
10 4.8
A) mean = 5.02 mmol/L, s = 0.175 mmol/L, %CV = 3.5
B) mean = 3.5 mmol/L, s = 0.175 mmol/L, %CV = 5.0
C) mean = 5.20 mmol/L, s = 0.0175 mmol/L, %CV = 0.34
D) mean = 4.8 mmol/L, s = 3.5 mmol/L, %CV = 72.9
A
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