Why do not shear fractures form at 45° to ?1, where the resolved shear stress is at its maximum?
What will be an ideal response?
Answer: This is explained in Box 7.2, where it is illustrated how shear fracture initiation or reactivation is controlled not only by shear stress (which is at its maximum at the plane oriented at 45° to ?1), but also by the normal stress (high normal stress counteracts slip). The ideal balance between these two effects is found at an angle higher than 45°.
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