Calculate the flux of the field F across the closed plane curve C.F = e5xi + e2yj; the curve C is the closed counterclockwise path around the triangle with vertices at and

Question

A. 3e⁵( e^-1 - 1) + (1 - e⁶) - 4
B. 3e⁵(1 - e^-1) + (e⁶ - 1) + 4
C. 0
D. e⁵(1 - e^-5) + (e⁶ - 1) - 4

Answer 1

Answer: D