An ion having eleven protons, twelve neutrons, and ten electrons will have a charge of
A. +.
B. -.
C. ++.
D. --.
A. +.
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In Cell 3,
Consider the following plant cells floating in an open beaker containing 0.2M sucrose. By definition, an open beaker has a pressure potential 0 MPa. Assume that the cells have come to equilibrium with the solution in the beaker.
A. ?p = 0.0 MPa and ?w = -0.5 MPa.
B. ?p = 0.0 MPa and ?w = 0.0 MPa.
C. ?p = +0.5 MPa and ?w = -0.5 MPa.
D. ?p = -0.5 MPa and ?w = -0.5 MPa.
E. ?p = 0.0 MPa and ?w = +0.5 MPa.
Clarify Question
What is the key concept addressed by the question?
What type of thinking is required?
What key words does the question contain and what do they mean?
Gather Content
What do you already know about water potential? How does it relate to the question?
Consider Possibilities
What other information is related to the question? Which information is most useful?
Choose Answer
Given what you now know, what information and/or problem solving approach is most likely to produce the correct answer?
Reflect on Process
Did your problem-solving process lead you to the correct answer? If not, where did the process break down or lead you astray? How can you revise your approach to produce a more desirable result?
Water moves up a plant via
a. capillaries. b. phloem. c. xylem. d. stomates. e. panicles.
As a result of an accident, a patient has their jaw wired shut and is put on a liquid diet. Why has the person been placed on a liquid diet?
A. Mechanical digestion would be inhibited since the jaws could not drive the breakdown of food by teeth. B. The secretion of amylase would be inhibited since muscles could not work. C. Peristalsis would stop. D. Lipase would not be added to food. E. None of the answer choices is correct.
____ plants do not develop aerial parts that are composed of lignin
a. Herbaceous b. Woody c. Deciduous d. Evergreen e. Shrub