Complete the square and write the equation in standard form. Then give the center and radius of the circle.x2 + y2 - 12x - 6y + 33 = 0
A. (x + 6)2 +(y + 3)2 = 12
(-6, -3), r = 2
B. (x - 6)2 +(y - 3)2 = 12
(-6, -3), r = 2
C. (x - 6)2 +(y - 3)2 = 12
(6, 3), r = 2
D. (x - 6)2 +(y - 3)2 = 12
(6, 3), r = 12
Answer: C
Mathematics
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