Evaluate the given function. Round to the nearest thousandth.f(x) = ex+ 3, f(2)
A. 10.389
B. 148.413
C. 7.718
D. 22.086
Answer: B
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Solve the problem.A 2,000-L tank is initially filled with a copper sulfate solution with a concentration of 50 g/L. A copper sulfate solution with a concentration of 20 g/L flows into the tank at a rate of 8 L/min. The thoroughly mixed solution is drained from the tank at a rate of 8 L/min.(a) Write an initial value problem for the mass of the copper sulfate.(b) Solve the initial value problem.
A. (a) m'(t) = 0.004m + 160, m(0) = 50 (b) m = -39,950e0.004t + 320,000 B. (a) m'(t) = -0.004m + 20, m(0) = 50 (b) m = -39,950e-0.004t + 40,000 C. (a) m'(t) = -250m + 160, m(0) = 100,000 (b) m = 60,000e-0.004t + 320,000 D. (a) m'(t) = -0.004m + 160, m(0) = 100,000 (b) m = 60,000e-0.004t + 40,000
Add.
A. 9919 B. 10,009 C. 10,019 D. 11,019
Solve the problem.A small frictionless cart, attached to the wall by a spring, is pulled 10 cm back from its rest position and released at time t = 0 to roll back and forth for 4 sec. Its position at time t is 
. What is the cart's maximum speed? When is the cart moving that fast? What is the magnitude of of the acceleration then?
A. 10? ? 31.42 cm/sec; t = 0 sec, 1 sec, 2 sec, 3 sec; acceleration is 0 cm/sec2 B. 10? ? 31.42 cm/sec; t = 0.5 sec, 1.5 sec, 2.5 sec, 3.5 sec; acceleration is 0 cm/sec2 C. 10? ? 31.42 cm/sec; t = 0.5 sec, 2.5 sec; acceleration is 1 cm/sec2 D. ? ? 3.14 cm/sec; t = 0.5 sec, 1.5 sec, 2.5 sec, 3.5 sec; acceleration is 0 cm/sec2
Solve.The formula for the area of a trapezoid is A = 
(b + B)h. Solve the formula for h. Use this formula to find the height of the trapezoid if the area, A, is 50 square meters, and the bases, b and B, are 12 meters and 13 meters.
A. h = 4 meters
B. h = 37
meters
C. h = 156 meters
D. h = 12
meters