Today is Kwaku’s 12 birthday and his father’s 40 birthday.How many years from today will Kwaku's father be twice as old as Kwaku is at that time?
(A) 12
(B) 14
(C) 16
(D) 18
(E) 20
Answer: (C) 16
Kwaku’s age = 12
father's age = 40
let after 'x' years father's age will be twice that of Kwaku’s age at that time
therefore
Kwaku’s age after x years = 12 + x
father's age after x years = 40 + x
after x years father will twice as old as Kwaku’s at that time => (12 + x) * 2 = 40 + x
x = 40 -24 = 16 (option C)
You might also like to view...
Find the length of the unknown side of the right triangle.The length of one leg is 15 meters, and the length of the hypotenuse is 39 meters.
A. 42 m B. 27 m C. 37 m D. 36 m
Determine whether the graph has an Euler path that begins and ends at different vertices. If the graph has such a path, say at which vertices the path must begin and end.
A. Yes; E and G B. No C. Yes; F and E D. Yes; C and G
Solve the equation.2(y + 8) = 3(y - 8)
A. -40 B. 40 C. 8 D. -8
Solve.|x - 3| > 0.3
A. (-?, ?) B. (-?, 2.7] ? [3.3, ?) C. (2.7, 3.3) D. (-?, 2.7) ? (3.3, ?)